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e3e87055bd
Fix regex escape warning in _coverage.py by using raw string #2819 while i am running '_coverage.py' I noticed there is a syntax warning:"\." It is an invalid escape sequence The regex was written as a normal string with '\.' which is not valid escape in string literals and give problems and error in a new python versions. To fix this switch to raw string(r'cv2?\.\w+') which can passes the backslashes directly to the regex engine. This removes the warning and keeps the code and pattern working properly. This is a small fix but important for future compatibilities.
30 lines
797 B
Python
Executable File
30 lines
797 B
Python
Executable File
#!/usr/bin/env python
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'''
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Utility for measuring python opencv API coverage by samples.
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'''
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# Python 2/3 compatibility
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from __future__ import print_function
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from glob import glob
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import cv2 as cv
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import re
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if __name__ == '__main__':
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cv2_callable = set(['cv.'+name for name in dir(cv) if callable( getattr(cv, name) )])
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found = set()
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for fn in glob('*.py'):
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print(' --- ', fn)
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code = open(fn).read()
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found |= set(re.findall(r'cv2?\.\w+', code))
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cv2_used = found & cv2_callable
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cv2_unused = cv2_callable - cv2_used
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with open('unused_api.txt', 'w') as f:
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f.write('\n'.join(sorted(cv2_unused)))
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r = 1.0 * len(cv2_used) / len(cv2_callable)
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print('\ncv api coverage: %d / %d (%.1f%%)' % ( len(cv2_used), len(cv2_callable), r*100 ))
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